The formula is $M_2O_3$. The ratio of Metal to Oxygen is $2:3$. $$ \textMoles M = \frac23 \times (\textMoles O) $$ $$ \textMoles M = \frac23 \times 0.0132\text mol = 0.00880\text mol $$
Below are key solutions and concepts for specific questions from that year: Acid-Base & Stoichiometry (Question 1) This problem involved a 5.00-gram mixture of KOHcap K cap O cap H K2CO3cap K sub 2 cap C cap O sub 3 KClcap K cap C l reacting with HClcap H cap C l : You must determine the percentage of K2CO3cap K sub 2 cap C cap O sub 3 by calculating the moles of CO2cap C cap O sub 2 gas produced ( ). Using the stoichiometry of 1972 ap chemistry free response answers
1-bromo-1-chloroethene vs. 1-bromo-2-chloroethene. The formula is $M_2O_3$